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			41 lines
		
	
	
		
			2.0 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
| <p>There are several consecutive houses along a street, each of which has some money inside. There is also a robber, who wants to steal money from the homes, but he <strong>refuses to steal from adjacent homes</strong>.</p>
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| 
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| <p>The <strong>capability</strong> of the robber is the maximum amount of money he steals from one house of all the houses he robbed.</p>
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| 
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| <p>You are given an integer array <code>nums</code> representing how much money is stashed in each house. More formally, the <code>i<sup>th</sup></code> house from the left has <code>nums[i]</code> dollars.</p>
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| 
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| <p>You are also given an integer <code>k</code>, representing the <strong>minimum</strong> number of houses the robber will steal from. It is always possible to steal at least <code>k</code> houses.</p>
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| 
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| <p>Return <em>the <strong>minimum</strong> capability of the robber out of all the possible ways to steal at least </em><code>k</code><em> houses</em>.</p>
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| 
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| <p> </p>
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| <p><strong class="example">Example 1:</strong></p>
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| 
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| <pre>
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| <strong>Input:</strong> nums = [2,3,5,9], k = 2
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| <strong>Output:</strong> 5
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| <strong>Explanation:</strong> 
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| There are three ways to rob at least 2 houses:
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| - Rob the houses at indices 0 and 2. Capability is max(nums[0], nums[2]) = 5.
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| - Rob the houses at indices 0 and 3. Capability is max(nums[0], nums[3]) = 9.
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| - Rob the houses at indices 1 and 3. Capability is max(nums[1], nums[3]) = 9.
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| Therefore, we return min(5, 9, 9) = 5.
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| </pre>
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| 
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| <p><strong class="example">Example 2:</strong></p>
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| 
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| <pre>
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| <strong>Input:</strong> nums = [2,7,9,3,1], k = 2
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| <strong>Output:</strong> 2
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| <strong>Explanation:</strong> There are 7 ways to rob the houses. The way which leads to minimum capability is to rob the house at index 0 and 4. Return max(nums[0], nums[4]) = 2.
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| </pre>
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| 
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| <p> </p>
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| <p><strong>Constraints:</strong></p>
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| 
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| <ul>
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| 	<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
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| 	<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>
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| 	<li><code>1 <= k <= (nums.length + 1)/2</code></li>
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| </ul>
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